Has any of you an idea about what the problem could be? I would like to also point out that the square roots are always well definite for the values I consider.It seems that Mathematica's handling of principal value integrals fails on some corner cases. substituting the values of Mu and u in the ugly formula and taking the difference). if I additionally specify a precise value of Mu (so it knows Mu + boundary of integration), in one lucky case it is able to directly give me the result for the definite integral this does not match with the value I would obtain by using the fundamental theorem of calculus (i.e.if I give precise values for the boundary (e.g, u=+-1/2), after a long time it just returns the definite integral without any result.if I keep the integral indefinite, it returns me a solution (quite ugly, but at least.):.So we’re especially excited to announce that Step-by-step solutions for these are now available The general method used to find the steps for definite integrals is to tap into the already existing Show steps functionality for indefinite integration, and then to.

int cos (et) dt int cos (u)/u du Ci (u) + c Ci (et) + c, where the second equality is by definition. One of the most popular queries on WolframAlpha is for definite integrals. Only for some specific case of Mu Mathematica seems to be able to compute it. To see this, substitute u et, du etdt, i.e. I'm trying to compute the following definite integral (Mu is a parameter): Integrate/Sqrt]], ] is an option for functions such as Simplify, Refine, and Integrate that specifies default assumptions to be made about symbolic quantities. Finance, Statistics & Business Analysis.Wolfram Knowledgebase Curated computable knowledge powering Wolfram|Alpha. Wolfram Universal Deployment System Instant deployment across cloud, desktop, mobile, and more. Wolfram Data Framework Semantic framework for real-world data.

Definite integral wolfram mathematica